(x^2-10x+25)=51

Solution for (x^2-10x+25)=51 equation:

(x^2-10x+25)=51

We move all terms to the left:

(x^2-10x+25)-(51)=0

We get rid of parentheses

x^2-10x+25-51=0

We add all the numbers together, and all the variables

x^2-10x-26=0

a = 1; b = -10; c = -26;
Δ = b2-4ac
Δ = -102-4·1·(-26)
Δ = 204
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{204}=\sqrt{4*51}=\sqrt{4}*\sqrt{51}=2\sqrt{51}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{51}}{2*1}=\frac{10-2\sqrt{51}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{51}}{2*1}=\frac{10+2\sqrt{51}}{2}
$